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Old Nov 05, 2006, 1:35pm   #1
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Default Probabilities question

So I have a weekly home game with some friends, a 5-7 person tournament. The blind structure is pretty bizarre, and it frequently results in, when we get heads-up, both players being all-in or pot-committed before they've even seen their cards. (Sounds awful but over the last month I'm running an ROI of >100%, so whatever.)

Anyway, I'm wondering what the relationship is between stack sizes and chance of winning in this situation. That is, if player A has a chips, and player B has b chips, and they're both going all-in PF every hand, what is A's chance of winning? Is it as simple as a/(a+b)?
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Old Nov 05, 2006, 2:02pm   #2
Lord Mushroom
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Originally Posted by AMDeluxe View Post
Is it as simple as a/(a+b)?

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